This is a multi-part message in MIME format. ---------------------- multipart/alternative attachment I'm not really looking for the partials of the notes, I am trying to = determine the best octave for an individual piano. If there is a lot of = inharmonicity, sometimes a 4:2 is too wide for the 2:1. If you know all = of the partial values in cents, how would you determine octave widths = that fit the best.=20 A2 1st partial =20 =20 2nd partial -6.72 =20 3nd partial -4.52 =20 4nd partial -2.57 =20 5nd partial 0.48 =20 6nd partial 3.27 =20 7nd partial 6.92 =20 8nd partial 5.85 =20 =20 A3 1st partial -1.06 =20 2nd partial -1.84 =20 3nd partial 0.33 =20 4nd partial 3.1 =20 5nd partial 6.88 =20 6nd partial 11.36 =20 7nd partial 15.23 =20 8nd partial 20.3 =20 A4 1st partial 0 =20 2nd partial 1.27 =20 3nd partial 4.28 =20 4nd partial 9.99 =20 5nd partial 15.99 =20 6nd partial 23.27 =20 7nd partial 31.84 =20 8nd partial 41.46 =20 This is A2 , A3 and A4 from a Wurlitzer spinet, we know all of the = information of the partials and can see how much stretch there needs to = be. Is there a way to determine the beat rate of any type of octave = from these numbers. Is a 6:3 too wide in the tenor, probably, can these = numbers prove that. If I tuned a 4:2 octave, what would the beat rate = be of the 2:1. It is not the octave type that I need but determining = which one fits the best to give me fairly clean octaves. I believe the = RCT has some of those capabilities to combine beats and cents = measurements into its calculations, but what is the best way to take = cents measurements and determine beat values? ---------------------- multipart/alternative attachment An HTML attachment was scrubbed... URL: https://www.moypiano.com/ptg/pianotech.php/attachments/dd/3c/d9/a6/attachment.htm ---------------------- multipart/alternative attachment--
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