---------------------- multipart/alternative attachment While I was digging about the net on this one I ran into the following: The following is THE equation for EVERYTHING you desire (and then some): n * sqrt(T/u) f = ------------ 2L f = the frequency of a streched string (or wire) n = 1 for FUNDAMENTAL frequency (which is what we want) T = Tension in wire u = (actually a greek mu) mass per unit length of wire Solve this for T and we get T = 4 L^2 F^2 u The mass per unit length (mu) is defined as R A u = --- g R = (rho in greek) = density of wire material steel = 0.283 lb/in^3 brass = 0.310 lb/in^3 A = cross-sectional area of the wire (pi * r^2) or (pi * (d/2)^2) r = wire radius or d = wire diameter g = gravitational constant (32.2 ft/sec^2) This reduces to pi * (d/2)^2 * R * F^2 * L^2 T = ------------------------------ 96.6 (the 96.6 is (32.2 * 12 in/ft) / 4 ) so, for #8 steel wire (d = 0.020"), 16 in long, tuned to A (440 hz) it will be under 45.6 lbs tension! You will need to dig up a table of string #s to find the diameter (#6 = 0.016" #8 = 0.020" #10 = 0.024" #12 = 0.029") and other densities if you don't use steel or brass wire. ANY college physics book should also have these equations as well as the wire diameter table and the wire densities. Just in case anybody is interested....grin > Djalma Carvalho - Brazil -- Richard Brekne RPT, N.P.T.F. Bergen, Norway mailto:Richard.Brekne@grieg.uib.no ---------------------- multipart/alternative attachment An HTML attachment was scrubbed... URL: https://www.moypiano.com/ptg/pianotech.php/attachments/41/13/cf/01/attachment.htm ---------------------- multipart/alternative attachment--
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