Age

[Richard Brekne]

Congrats John and Susan for solving this ever so little puzzel. John came up
with the Algebra, but Susan of course choose the easiest route, tho that had
nothing to do with finding an algebraic solution.

Nice to know some of us can still figure these little high school math
problems.. grin.. amazing how many parents get stuck when their kids come home
from school asking for help on these.

Anyways, thanks you two... for playing along.

Susan Kline wrote:

> John, you truly followed instructions.
>
> What I did was subtract 22 from 54, and figured out that
> she started when she was 32. Assuming that she doesn't take
> a few years off, one could just double 32, and get 64.
>
> By one of those strange coincidences, I'm also 54, and
> also started when I was 32.
>
> Susan
>
> >OK here goes:
> >Let X = years to go to meet requirement
> >Let A = age when requirements are met
> >Solve for age A when number of years of experience equal 1/2 of age.
> >
> >Given:  Current age of 54 and experience of 22 ( 54-22=32 or age starting
> >experience.)
> >(X+32)+(X+22)=54+X  (years to go to meet requirement)
> >
> >X+22=(54+X)/2
> >2X+44=54+X
> >X+44=54
> >X=10
> >
> >A=54+X
> >A=64!!!!!!!!!!!!!! (almost time to retire)
> >
> >(And I did all this AFTER tuning 8 pianos and installing a set of
> >castors)
> >You people just ask too much of me:-)
> >
> >Oh, Diane -  Happy Birthday!
> >
> >John R. Fortiner
> >Billings, MT.
> >
> >
> >On Wed, 03 May 2000 22:01:56 +0200 Richard Brekne <richardb@c2i.net>
> >
> > > ok you math genuises... grin... how many years before
> > > Diane will have spent half her life as a technician ???
> > > Can any of you's write out an algebraic solution ?

--
Richard Brekne
Associate PTG, N.P.T.F.
Bergen, Norway