Hi... no bites on this so I thought I might try phrasing it a different way and see if I could get any feedback. If the string terminations were infinitely stiff, then there would be no mechanism for string coupling .... yes ? You could in theory have a piano unison, excite the strings in the usual way with the hammer.... but the infinite stiff terminations would not allow for any coupling, there by the strings would each vibrate completely independent of one another. Ok.... so add a set of non infinitely stiff bridge pins and leave everything else about the terminations infinitely stiff. You still have the same situation, tho the bridge pins become some form or another of an extension of the string. Perhaps this scenario would open for false beats on individual strings at best, but there is still no mechanism for the three strings to couple given the infinite resistance to vibration by the bridge itself. So no pitch drop due to coupling is possible as no coupling is possible to begin with. Yes ??... So at some point the bridge becomes non-stiff enough to allow for this coupling. And the more non-stiff the bridges becomes... the greater the ability for the strings to couple, hence the greater their influence on each other... and hence the more evident (greater degree ?) of pitch drop.... Or what ? Cheers RicB Got to thinking abit about string coupling and the mechanisms that are at work that account for the pitch drop and got to wondering if it is viable to think of the degree of pitch drop when 2 and 3 strings are coupled in on a unison as an indicator of SB/bridge stiffness at any given note. Or... is this another one of my rabbit holes ? Cheers RicB
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