Octave Tuning

[Don]

Hi,

I believe the problem is semantics. If you add a M6 and a p12 the result is
a M17. What Richard is suggesting is that the M6 and the M17 beat at the
same speed, as a "proof" of the p12.

f2--d3 = M6
f2--a4 = M17

if M6 beats at same rate as M17, then d3--a4 = p12

As this is an "outside" test (f2 is not between d3 and a4) it doesn't
matter if f2 is flat or sharp.

At 08:43 PM 23/09/2004 +0100, you wrote:
>Ok.. once more....
>
>take any ol 12th... say    D3 - A4.  The major sixth below the lowest 
>note of this particular 12th is F2.  These three notes share a 
>coincident at A4 (1)... i.e.  the fundemental of A4.
>
>So.... to insure the D3(3) is just with A4(1)... i.e. a pure 12th.... 
>then the beat rates of both D3(3) and A4(1) against F2(5) will be the same.
>
>This works for any 12th... just take the major sixth below the lowest 
>note, play that with each note of the 12th and compare the beat 
>resultant rates. Ric,

Regards,
Don Rose, B.Mus., A.M.U.S., A.MUS., R.P.T.

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