Ron, I'm asking you this question since you are largely responsible for encouraging me to get carried away (according to some) in modifying this Emerson piano for the vertical hitch pins. I saved this post about the Lowell gauge. My plans are to string the plain wires, bring it up to about one step flat and then adjust the down bearing. What angle in the different sections should I shoot for under those conditions? It's easier to adjust before installing the bass strings. Then I'll string the bass and do likewise. Your recommendations and comments welcomed. Thanks. Carl Meyer Assoc. PTG Santa Clara, California cmpiano@attbi.com ----- Original Message ----- From: "Ron Nossaman" <RNossaman@KSCABLE.com> To: <pianotech@ptg.org> Sent: Friday, October 12, 2001 3:22 PM Subject: Re: Lowell guage > >Hi list, > > Does anyone still have the original lowell downbearing gauge > >instructions , that tell what the scale markings are supposed to be > >calibrated to? For fun I went to the Baldwin class at Sparks and the > >Baldwin people disagreed with Mr. Lowell as to the actual degrees that > >the bubble markings corresponded to. But I can't find my notes, > >soooooo............... > > > >Thanks > > > >Dale Fox > > > > Here you go Dale, Tom sent me this some time back. > > > In brief, the thousandths of an inch quantities represented by the linear > increments (division lines) on the gauge are the rise or fall (vertical > dimension) per inch of length of piano string. So, to give an example, if > your rear string length > was 3" and your gauge measurement was .009", then the difference in elevation > between the top of the bridge (a reference at zero), and the rear string > rest would be 3" x .009" or .027". Very simple math. These dimensions can > be converted to degrees of angle by multiplying 1/6 degree times the number > of division lines the bubble has crossed. Crossing six division lines would > mean 1 full degree of string angle. More simple math. To determine the lbs. > pressure > from the net downbearing measurement multiply the net bearing in thousandths > of an inch by the tension of the string. For example, a string of 200 lbs > tension, deflected by the bridge so that a net downbearing measurement of > .018" (1 degree) is created, will produce a downbearing pressure of 3.6 lbs. > (200 x .018). More simple math. Incidentally, the bridge is pushing up at > the string 3.6 lbs. at the same time the string is pushing down on the bridge, > thus creating a static equilibrium, like a depressed spring. An > understanding of trigonometry is unnecessary, but can't hurt anyone. > > > Ron N
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