Inertia

Ron Nossaman RNossaman@cox.net
Wed, 31 Dec 2003 01:18:19 -0600


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> > And since the leads are there to counterbalance the hammer weight (etc.),
> > did you double the weight of the lead when you halved the length of the 
> moment?
> >
>
>Ron, given my limits in mathematics, rather than defend my calculations, I 
>would
>prefer that someone like you would do a few of your own, and tell us what 
>you get.

It's not a math problem Ed, it's a conceptual one. Why are leads put in 
keys in the first place if not to counteract hammer (etc) weight for a 
nominally specific static down weight? Moving the weight to a different 
point on the key requires a different amount of weight for the same 
balance, which changes your inertia calculation. You didn't take that into 
account.


> > >Again I suspect that the difference would be in speed of repetition.
> >
> > Probably, all else being equal, and depending on how much key lead is
> > actually removed. It has to become noticeable in the power stroke too, at
> > some threshold level.
> >
> > Ron N
> >
>
>Ron, could you expand on your last sentence, please?
>
>Ed

What's to expand on? At some degree of mass difference a light key will 
feel noticeably different from a heavy key when you push it down to play 
it, even with a wippen assist spring making the down weights identical.

Ron N

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