>A string deflection angle of 17 minutes (0º 17') of arc yields a string >bearing against the bridge of 0.5%. There are 60' of arc per degree. > >Del And 17' of arc is 17/60 = 0.28333etc°. So in Excel, SIN(RADIANS(17/60)) = 0.004945 (0.5%) per division, * tension = down bearing per division. One bubble division at 540 lbs for the unison = 2.67 lbs - or thereabout. Ron N
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